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对于bigeagle的树状结构存储过程的一些看法

对于bigeagle的树状结构存储过程的一些看法

更新时间:2021-01-08 文章作者:未知 信息来源:网络 阅读次数:

大鹰,关于你在精华区的树状结构存储过程的贴子的内容好像不对呀,我做了实验,只能取根帖,我改了一下,在query analyzer中可以,但在页面上只能显示出一部分,你帮忙看一下好吗 
CREATE proc up_TopicList
@a_ForumID int ,@a_intPageNo int , @a_intPageSize tinyint
 as
 declare @m_intRecordNumber int
 declare @m_intStartRecordint
 declare @m_intRootIDint
 select @m_intRecordNumber = @a_intPageSize * @a_intPageNo
 select @m_intStartRecord = @a_intPageSize * (@a_intPageNo - 1) + 1


/*求符合条件记录数*/
select "RecordCount" = count(*) 
 from BBS where Layer=1 and ForumID = @a_ForumID

 /*输出纪录*/
 /*首先定义可滚动光标*/
 set rowcount @m_intRecordNumber
 declare m_curTemp Scroll cursor
 for
select 'rootID'=a.rootID 
from BBS as a
 join BBSUser as d on a.UserID = d.[ID]
where a.Layer=1 and a.ForumID = @a_ForumID
order by RootID desc , Layer , PostTime desc
 open m_curTemp
 fetch absolute @m_intStartRecord from m_curTemp into @m_intRootID
 
 while(@@fetch_status = 0)
begin
select 'ID' = a.[ID] ,
'Title' = a.Title ,
'UserName' = d.UserName ,
'Hits' = a.Hits,
'Face' = a.Face ,
'Layer'=a.Layer,
'ContentSize' = datalength(a.Content) ,
'TotalChilds' = (select sum(TotalChilds)
from BBS as b
where a.RootID = b.RootID) ,
'LastReplyTime' = a.PostTime
 
from BBS as a
 join BBSUser as d on a.UserID = d.[ID]
where a.Layer>=1 and a.ForumID = @a_ForumID and a.rootID=@m_intRootID
order by RootID desc , Layer , PostTime desc
fetch next from m_curTemp into @m_intRootID
end
 set rowcount 0
 /*清场*/ 
 CLOSE m_curTemp
 DEALLOCATE m_curTemp
GO

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